Comparer deux dates avec JavaScript

Mots clés : javascriptdatedatetimecomparejavascript

meilleur 5 Réponses Comparer deux dates avec JavaScript

vote vote

100

var d1 = new Date(); var d2 = new Date(d1); var same = d1.getTime() === d2.getTime(); var notSame = d1.getTime() !== d2.getTime(); 
var d1 = new Date(); var d2 = new Date(d1);  console.log(d1 == d2);   // prints false (wrong!)  console.log(d1 === d2);  // prints false (wrong!) console.log(d1 != d2);   // prints true  (wrong!) console.log(d1 !== d2);  // prints true  (wrong!) console.log(d1.getTime() === d2.getTime()); // prints true (correct) 
vote vote

82

// Source: http://stackoverflow.com/questions/497790 var dates = {     convert:function(d) {         // Converts the date in d to a date-object. The input can be:         //   a date object: returned without modification         //  an array      : Interpreted as [year,month,day]. NOTE: month is 0-11.         //   a number     : Interpreted as number of milliseconds         //                  since 1 Jan 1970 (a timestamp)          //   a string     : Any format supported by the javascript engine, like         //                  "YYYY/MM/DD", "MM/DD/YYYY", "Jan 31 2009" etc.         //  an object     : Interpreted as an object with year, month and date         //                  attributes.  **NOTE** month is 0-11.         return (             d.constructor === Date ? d :             d.constructor === Array ? new Date(d[0],d[1],d[2]) :             d.constructor === Number ? new Date(d) :             d.constructor === String ? new Date(d) :             typeof d === "object" ? new Date(d.year,d.month,d.date) :             NaN         );     },     compare:function(a,b) {         // Compare two dates (could be of any type supported by the convert         // function above) and returns:         //  -1 : if a < b         //   0 : if a = b         //   1 : if a > b         // NaN : if a or b is an illegal date         // NOTE: The code inside isFinite does an assignment (=).         return (             isFinite(a=this.convert(a).valueOf()) &&             isFinite(b=this.convert(b).valueOf()) ?             (a>b)-(a<b) :             NaN         );     },     inRange:function(d,start,end) {         // Checks if date in d is between dates in start and end.         // Returns a boolean or NaN:         //    true  : if d is between start and end (inclusive)         //    false : if d is before start or after end         //    NaN   : if one or more of the dates is illegal.         // NOTE: The code inside isFinite does an assignment (=).        return (             isFinite(d=this.convert(d).valueOf()) &&             isFinite(start=this.convert(start).valueOf()) &&             isFinite(end=this.convert(end).valueOf()) ?             start <= d && d <= end :             NaN         );     } } 
vote vote

76

const x = new Date('2013-05-23'); const y = new Date('2013-05-23');  // less than, greater than is fine: console.log('x < y', x < y); // false console.log('x > y', x > y); // false console.log('x <= y', x <= y); // true console.log('x >= y', x >= y); // true console.log('x === y', x === y); // false, oops!  // anything involving '==' or '===' should use the '+' prefix // it will then compare the dates' millisecond values  console.log('+x === +y', +x === +y); // true
vote vote

67

var d1 = new Date(2013, 0, 1); var d2 = new Date(2013, 0, 2); d1 <  d2; // true d1 <= d2; // true d1 >  d2; // false d1 >= d2; // false 
var d1 = new Date(2013, 0, 1); var d2 = new Date(2013, 0, 1); /*  * note: d1 == d2 returns false as described above  */ d1.getTime() == d2.getTime(); // true d1.valueOf() == d2.valueOf(); // true Number(d1)   == Number(d2);   // true +d1          == +d2;          // true 
vote vote

55

var oDateOne = new Date();  var oDateTwo = new Date();    alert(oDateOne - oDateTwo === 0);  alert(oDateOne - oDateTwo < 0);  alert(oDateOne - oDateTwo > 0);

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