python - Comment puis-je trier un dictionnaire par valeur

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>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} >>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])} {0: 0, 2: 1, 1: 2, 4: 3, 3: 4} 

>>> dict(sorted(x.items(), key=lambda item: item[1])) {0: 0, 2: 1, 1: 2, 4: 3, 3: 4} 

import operator x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} sorted_x = sorted(x.items(), key=operator.itemgetter(1)) 

import operator x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} sorted_x = sorted(x.items(), key=operator.itemgetter(0)) 

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} sorted_x = sorted(x.items(), key=lambda kv: kv[1]) 

import collections  sorted_dict = collections.OrderedDict(sorted_x) 

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from collections import defaultdict d = defaultdict(int) for w in text.split():     d[w] += 1 

for w in sorted(d, key=d.get, reverse=True):     print(w, d[w]) 

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sorted(d.items(), key=lambda x: x[1]) 

sorted(d.items(), key=lambda x: x[1], reverse=True) 

d = {'one':1,'three':3,'five':5,'two':2,'four':4} a = sorted(d.items(), key=lambda x: x[1])     print(a) 

[('one', 1), ('two', 2), ('three', 3), ('four', 4), ('five', 5)] 

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sorted(d.values()) 

from operator import itemgetter sorted(d.items(), key=itemgetter(1)) 

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>>> d = {"third": 3, "first": 1, "fourth": 4, "second": 2}  >>> for k, v in d.items(): ...     print "%s: %s" % (k, v) ... second: 2 fourth: 4 third: 3 first: 1  >>> d {'second': 2, 'fourth': 4, 'third': 3, 'first': 1} 

>>> from collections import OrderedDict >>> d_sorted_by_value = OrderedDict(sorted(d.items(), key=lambda x: x[1])) 

>>> for k, v in d_sorted_by_value.items(): ...     print "%s: %s" % (k, v) ... first: 1 second: 2 third: 3 fourth: 4  >>> d_sorted_by_value OrderedDict([('first': 1), ('second': 2), ('third': 3), ('fourth': 4)])